Optimal. Leaf size=209 \[ \frac{(e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{b x^2}{a}\right ) (A b (1-m) (a d (m+1)+b c (3-m))+a B (m+1) (a d (m+3)+b (c-c m)))}{8 a^3 b^2 e (m+1)}-\frac{(e x)^{m+1} (A b (a d (1-m)-b c (3-m))-a B (b c (m+1)-a d (m+3)))}{8 a^2 b^2 e \left (a+b x^2\right )}+\frac{\left (c+d x^2\right ) (e x)^{m+1} (A b-a B)}{4 a b e \left (a+b x^2\right )^2} \]
[Out]
________________________________________________________________________________________
Rubi [A] time = 0.296005, antiderivative size = 209, normalized size of antiderivative = 1., number of steps used = 3, number of rules used = 3, integrand size = 29, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.103, Rules used = {577, 457, 364} \[ \frac{(e x)^{m+1} \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{b x^2}{a}\right ) (A b (1-m) (a d (m+1)+b c (3-m))+a B (m+1) (a d (m+3)+b (c-c m)))}{8 a^3 b^2 e (m+1)}-\frac{(e x)^{m+1} (A b (a d (1-m)-b c (3-m))-a B (b c (m+1)-a d (m+3)))}{8 a^2 b^2 e \left (a+b x^2\right )}+\frac{\left (c+d x^2\right ) (e x)^{m+1} (A b-a B)}{4 a b e \left (a+b x^2\right )^2} \]
Antiderivative was successfully verified.
[In]
[Out]
Rule 577
Rule 457
Rule 364
Rubi steps
\begin{align*} \int \frac{(e x)^m \left (A+B x^2\right ) \left (c+d x^2\right )}{\left (a+b x^2\right )^3} \, dx &=\frac{(A b-a B) (e x)^{1+m} \left (c+d x^2\right )}{4 a b e \left (a+b x^2\right )^2}-\frac{\int \frac{(e x)^m \left (-c (A b (3-m)+a B (1+m))-d (A b (1-m)+a B (3+m)) x^2\right )}{\left (a+b x^2\right )^2} \, dx}{4 a b}\\ &=-\frac{(A b (a d (1-m)-b c (3-m))-a B (b c (1+m)-a d (3+m))) (e x)^{1+m}}{8 a^2 b^2 e \left (a+b x^2\right )}+\frac{(A b-a B) (e x)^{1+m} \left (c+d x^2\right )}{4 a b e \left (a+b x^2\right )^2}-\frac{(b c (-1+m) (A b (3-m)+a B (1+m))-a d (1+m) (A b (1-m)+a B (3+m))) \int \frac{(e x)^m}{a+b x^2} \, dx}{8 a^2 b^2}\\ &=-\frac{(A b (a d (1-m)-b c (3-m))-a B (b c (1+m)-a d (3+m))) (e x)^{1+m}}{8 a^2 b^2 e \left (a+b x^2\right )}+\frac{(A b-a B) (e x)^{1+m} \left (c+d x^2\right )}{4 a b e \left (a+b x^2\right )^2}+\frac{(A b (1-m) (b c (3-m)+a d (1+m))+a B (1+m) (b c (1-m)+a d (3+m))) (e x)^{1+m} \, _2F_1\left (1,\frac{1+m}{2};\frac{3+m}{2};-\frac{b x^2}{a}\right )}{8 a^3 b^2 e (1+m)}\\ \end{align*}
Mathematica [A] time = 0.128198, size = 133, normalized size = 0.64 \[ \frac{x (e x)^m \left (a^2 B d \, _2F_1\left (1,\frac{m+1}{2};\frac{m+3}{2};-\frac{b x^2}{a}\right )+a \, _2F_1\left (2,\frac{m+1}{2};\frac{m+3}{2};-\frac{b x^2}{a}\right ) (-2 a B d+A b d+b B c)+(A b-a B) (b c-a d) \, _2F_1\left (3,\frac{m+1}{2};\frac{m+3}{2};-\frac{b x^2}{a}\right )\right )}{a^3 b^2 (m+1)} \]
Antiderivative was successfully verified.
[In]
[Out]
________________________________________________________________________________________
Maple [F] time = 0.056, size = 0, normalized size = 0. \begin{align*} \int{\frac{ \left ( ex \right ) ^{m} \left ( B{x}^{2}+A \right ) \left ( d{x}^{2}+c \right ) }{ \left ( b{x}^{2}+a \right ) ^{3}}}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{2} + A\right )}{\left (d x^{2} + c\right )} \left (e x\right )^{m}}{{\left (b x^{2} + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{{\left (B d x^{4} +{\left (B c + A d\right )} x^{2} + A c\right )} \left (e x\right )^{m}}{b^{3} x^{6} + 3 \, a b^{2} x^{4} + 3 \, a^{2} b x^{2} + a^{3}}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Sympy [F(-1)] time = 0., size = 0, normalized size = 0. \begin{align*} \text{Timed out} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]
________________________________________________________________________________________
Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{{\left (B x^{2} + A\right )}{\left (d x^{2} + c\right )} \left (e x\right )^{m}}{{\left (b x^{2} + a\right )}^{3}}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
[In]
[Out]